[SOLVED] Revolving counter


#1

Hi!
I have a revolving counter variable that counts until 255 and then reset.
Now I need to calculate a synthetic variable with it so I have variable -shift(variable,-1) so my problem is that when variable reset that subtraction will be negative and it couldn’t be.
Any tips on how can I still make shift operation but not having that problem?
I tried with where but do not know if it will work.
Kind regards,
Roberto.


#2

Hello Roberto,

The way I see it a simple abs() function would the trick. You can wrap your expression app with the abs()function as follows:

abs(var - shift(var, -1))

Hope this helps.


#3

Hi David,
If I remember correctly, the only thing abs does is return the value in positive, right?
Imagine current value 200 and previous 190; for this case it would be x = 10.
But if we put 5 and previous 255 for example, x = 250 and this would not be the correct result.
Thanks for the help.


#4

Roberto,

That’s quite right, I did not think correctly about the revolving condition. Nevertheless, now that I have, here is an expression that I’m sure works after giving a shot:

a =  var
b = shift(var, -1)
where (a > b, a - b, abs(255 - b + a))

Best,

–David


#5

Thanks @dsr I forgot I could just use variables as you writed…
Kind Regards!